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Lesson 16 min· Section 1 of 4

The straight-up lesson, built for the exam.

Progressions & Series

Formula sheet

Everything for this chapter, in one place. aa is the first term, dd the common difference, rr the common ratio, ll the last term, nn the number of terms.

Arithmetic progression — add the same dd each time

nnth termtn=a+(n−1)dt_n = a + (n-1)d
SumSn=n2[2a+(n−1)d]S_n = \dfrac{n}{2}\left[2a + (n-1)d\right]
Sum, when you know the last termSn=n2(a+l)S_n = \dfrac{n}{2}(a + l)
Term, from the sumtn=Sn−Sn−1t_n = S_n - S_{n-1}
Number of termsn=l−ad+1n = \dfrac{l-a}{d} + 1
Average of the whole APa+l2\dfrac{a+l}{2}, which is the middle term
Three terms in AP2b=a+c2b = a + c

Picking terms symmetrically — kills the algebra when a sum is given

3 termsa−d,  a,  a+da-d,\; a,\; a+d
4 termsa−3d,  a−d,  a+d,  a+3da-3d,\; a-d,\; a+d,\; a+3d — note the common difference is 2d2d
5 termsa−2d,  a−d,  a,  a+d,  a+2da-2d,\; a-d,\; a,\; a+d,\; a+2d

Geometric progression — multiply by the same rr each time

nnth termtn=arn−1t_n = ar^{n-1}
SumSn=a(rn−1)r−1S_n = \dfrac{a(r^n - 1)}{r - 1}, for r≠1r \neq 1
Infinite sumS∞=a1−rS_\infty = \dfrac{a}{1-r}, only when ∣r∣<1\lvert r \rvert < 1
Three terms in GPb2=acb^2 = ac
Arithmetico-geometric∑(a+kd)rk=a1−r+dr(1−r)2\sum (a+kd)r^k = \dfrac{a}{1-r} + \dfrac{dr}{(1-r)^2}, for ∣r∣<1\lvert r \rvert < 1

Means

AM, GM, HM of aa and bba+b2\dfrac{a+b}{2}, ab\sqrt{ab}, 2aba+b\dfrac{2ab}{a+b}
Always true for positivesAM≥GM≥HM\text{AM} \ge \text{GM} \ge \text{HM}, equal only when a=ba=b
HPthe reciprocals form an AP — there is no HP sum formula

Standard sums — worth knowing cold

1+2+⋯+n1 + 2 + \cdots + nn(n+1)2\dfrac{n(n+1)}{2}
12+22+⋯+n21^2 + 2^2 + \cdots + n^2n(n+1)(2n+1)6\dfrac{n(n+1)(2n+1)}{6}
13+23+⋯+n31^3 + 2^3 + \cdots + n^3[n(n+1)2]2\left[\dfrac{n(n+1)}{2}\right]^2
1+3+5+⋯1 + 3 + 5 + \cdots (nn odd terms)n2n^2

Telescoping — when a sum collapses

1a(a+d)\dfrac{1}{a(a+d)}1d(1a−1a+d)\dfrac{1}{d}\left(\dfrac{1}{a} - \dfrac{1}{a+d}\right)
1a+b\dfrac{1}{\sqrt{a}+\sqrt{b}}b−ab−a\dfrac{\sqrt{b}-\sqrt{a}}{b-a}
Products of consecutive AP termstktk+1=tktk+1tk+2−tk−1tktk+13dt_k t_{k+1} = \dfrac{t_k t_{k+1} t_{k+2} - t_{k-1} t_k t_{k+1}}{3d}

Why this chapter matters

1.5
questions in a typical Quant section
2nd
of 25 chapters

≈ 5 of 66 marks a section ride on it.

Asked in24 of 24 papers
20172025
Year by yearper section
  1. 2017: 1.6 per section
  2. 2018: 1.3 per section
  3. 2019: 1.9 per section
  4. 2020: 0.8 per section
  5. 2021: 1.7 per section
  6. 2022: 1.3 per section
  7. 2023: 2 per section
  8. 2024: 1 per section
  9. 2025: 1.7 per section
Question type41 asked
MCQ 78%Type-in 22%

Type-in answers carry no negative marking.

From every Progressions & Series question in CAT papers since 2017.